If the organism with the genotype Ab/aB produces 10% each of the crossover gametes, AB and ab in a test cross, what is the distance between A and B gene loci?
Question: If the organism with the genotype Ab/aB produces 10% each of the crossover gametes, AB and ab in a test cross, what is the distance between A and B gene loci?
Given:
Genotype of organism: Ab/aB
This is a repulsion (trans) heterozygote, meaning A is with b on one chromosome and a is with B on the other chromosome.
The organism is test crossed (i.e., crossed with ab/ab).
The crossover gametes are:
- AB = 10%
- ab = 10%
Total crossover frequency:
Crossover gametes are produced only due to recombination. In this case:
- AB and ab are the recombinant gametes
- Ab and aB are the parental (non-recombinant) gametes
So,
Crossover frequency = AB + ab = 10% + 10% = 20%
Distance between A and B gene loci:
In genetics, 1% recombination = 1 map unit (centiMorgan or cM)
So,
Distance between A and B = 20 cM
Answer: 20 cM
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